Electricity — AQA A-Level Physics

Current, Charge & Potential Difference

"Right now, roughly 10²⁰ electrons per second are passing through the phone or laptop you're using. They move at about the speed of a slow walk — so why does the light switch work instantly when you flip it?"

AQA A-Level ~50 min
● RED By the end of this lesson you will be able to:
Define electric current as the rate of flow of charge and use I = ΔQ / Δt
AQA 3.5.1.1
Explain the distinction between conventional current direction and the direction of electron flow
AQA 3.5.1.1
Define potential difference as energy transferred per unit charge and use V = W / Q
AQA 3.5.1.2
Identify different charge carriers (electrons in metals, ions in electrolytes) and calculate charge using Q = It
AQA 3.5.1.1 – 3.5.1.2
ENRICHMENT: Explain why drift velocity of electrons (~10⁻⁴ m s⁻¹) is far slower than the speed of signal propagation (~c) in a circuit
⚛ Invisible Physics — the hidden reality

What is actually happening inside a wire carrying 1 ampere

A copper wire carrying 1 A contains roughly 8 × 10²⁸ free electrons per cubic metre — one for every copper atom. Yet each electron only shuffles forward at around 0.1 mm per second, slower than a snail. There is no single electron that races from battery to bulb; instead, the entire sea of electrons nudges in one direction simultaneously, like a tube already full of ball bearings — push one in at one end, one pops out the other instantly.

Electron drift in a copper wire — scale diagram A cross-section of copper wire showing densely packed copper atoms as circles with tiny arrows showing the slow drift of electrons to the right, while the electric field signal propagates instantly at near light-speed. COPPER WIRE (cross-section) Cu⁺ ion free e⁻ (drift ~0.1 mm/s →) signal ~c ⚡
~10⁻⁴
Electron drift speed (m s⁻¹) at 1 A
8×10²⁸
Free electrons per m³ in copper
6×10¹⁸
Electrons per second past a point at 1 A
4

Core Content

Intuition → definition → formula → application
● RED
Maxwell
AQA Physics
1 / 6
Electric Current & Charge RED

Imagine water flowing through a pipe. The current is how much water passes a point per second. In a wire, the "water" is electric charge — mostly electrons in metals — and current is how much charge flows past a cross-section every second. The bigger the flow, the higher the current.

Electric current as charge flow through a cross-section of wire A wire shown as a cylinder with arrows indicating electrons moving left and conventional current arrow pointing right. A dashed cross-section plane shows charge Q passing in time t giving I = Q/t. Conventional current I → ← Electron flow (e⁻) Q coulombs pass in t seconds e⁻ e⁻ e⁻ e⁻

Conventional current flows positive → negative; electrons flow the opposite way. Both conventions describe the same physical situation.

Definition — Electric Current: The rate of flow of electric charge. Current I is defined as the charge ΔQ passing a point divided by the time interval Δt.
DEFINING EQUATION — Electric Current
I = ΔQ / Δt
I = current (A) | ΔQ = charge transferred (C) | Δt = time taken (s)
Rearranged: ΔQ = I Δt — charge = current × time
1 A = 1 C s⁻¹
Definition of the Ampere
1 coulomb per second through any cross-section
e = 1.6 × 10⁻¹⁹ C
Charge of one electron
1 A ≡ 6.25 × 10¹⁸ electrons per second
⭐ Exam tip
AQA uses ΔQ = IΔt (not Q = It) to signal that these are incremental quantities. When a question says "charge flows for 3 minutes", convert to seconds first: 3 × 60 = 180 s. Forgetting to convert time units is the single most common arithmetic error on this topic.
Common mistake: Saying "current flows" — current is not a substance. Current is a rate. The charge carriers (electrons) flow; the current is the rate at which they do so. Examiners penalise "current flows through the wire" in definition questions — say "charge flows" instead.
Potential Difference (Voltage) RED

Think of potential difference (pd) as the "push" that makes charges move. Specifically, it is the energy given to (or taken from) each coulomb of charge as it moves between two points. A 9 V battery gives 9 joules of energy to every coulomb of charge it pushes through the circuit. No pd — no current.

Potential difference: energy transferred per unit charge between two points Two points A and B connected by a component (resistor symbol). Arrow shows charge Q moving from A to B, with work done W labelled. The equation V = W/Q is shown. Component A B Q coulombs of charge move A→B, doing W joules of work V_AB = W / Q potential difference V (volts)

Potential difference is measured between two points — it is always a difference, never an absolute value (unless referenced to earth/ground).

Definition — Potential Difference: The potential difference between two points is the work done per unit charge moving between those points. V = W / Q, where W is in joules and Q in coulombs, giving volts (V = J C⁻¹).
DEFINING EQUATION — Potential Difference
V = W / Q
V = potential difference (V) | W = work done / energy transferred (J) | Q = charge (C)
1 volt = 1 joule per coulomb (1 V = 1 J C⁻¹)
⭐ Exam tip
AQA defines pd as "energy transferred per unit charge." The phrase "per unit charge" (i.e. per coulomb) must appear in your definition — writing "energy transferred by charge" without "per unit" loses the mark. The examiner is testing whether you understand it's a ratio.
Common mistake: Confusing "voltage" with "energy." A 9 V battery does not contain 9 J — it gives 9 J per coulomb. How much total energy it stores depends on how much charge it can deliver (amp-hours). Examiners frequently test this distinction.
Charge Carriers AMBER

Not all conductors use electrons. In metals, the charge carriers are delocalised electrons (negative, moving opposite to conventional current). In electrolyte solutions (e.g. salt water, batteries), both positive and negative ions carry charge. In semiconductors, both electrons and "holes" (positive vacancies) carry current. The type of carrier affects how the material behaves.

Key carriers to know:
Metals: free (delocalised) electrons — negative charge carriers
Electrolytes: positive and negative ions
Semiconductors: electrons and holes
Gases (discharge tubes): positive ions and electrons
⭐ Exam tip
When asked "what are the charge carriers in a metal?" — always say "delocalised (free) electrons". Writing just "electrons" is acceptable, but "delocalised electrons" secures the mark and shows A-Level understanding. Never say "protons" carry charge in a metal — protons are fixed in the lattice.
TIER A — Syllabus Support (RED / AMBER)
TIER B — Conceptual Enrichment (GREEN)
TIER C — Beyond Beyond (BLUE / GREY) · No exam relevance · Pure wonder
5

Checkpoint

Answer before moving forward
● RED — gated
Checkpoint Question 1
Define electric current and write the equation that relates current, charge and time. Then: a kettle draws a current of 10 A for 2.5 minutes. Calculate the charge that flows through the element in that time. Show your working and give the unit.
6

TEACH IT

Explain it to a confused student
● RED — mandatory
TEACH IT
Explain current, charge and potential difference to a confused student

A confused student is waiting. They have been reading but they do not quite get it. They will ask you questions, offer wrong explanations and ask if they are right, and push back when your explanation is vague. Explain current, charge and potential difference until they understand. This is the deepest test in the lesson — you do not really know something until you can teach it.

7

Virtual Lab

Set up · measure · plot · conclude
● AMBER
Investigating the Relationship Between Current, Charge and Time — PhET Circuit Construction Kit

Using the PhET Circuit Construction Kit (DC), you will build a simple series circuit and use an ammeter and clock to measure how charge accumulates over time at different current settings. You must record all data manually — the simulation does not auto-record. Plot charge Q (y-axis) against time t (x-axis) for three different current settings, draw best-fit straight lines through the origin, and calculate the gradient (= current I) from each.

Open virtual experiment
1
Set the current to I = 1.0 A. Record charge Q at t = 0, 30, 60, 90, 120, 150 s from the simulated coulomb-meter. Record to 3 significant figures.
2
Repeat for I = 2.0 A and I = 0.5 A. Plot all three data sets on the same axes (Q vs t). Draw a best-fit straight line through the origin for each set.
3
Calculate the gradient of each line. Compare to the set current value. Do the gradients match I? This confirms ΔQ = IΔt experimentally.
4
Conclusion: state whether your graph supports Q = It. Give the percentage difference between your measured gradient and the set current value. Suggest one source of systematic uncertainty.
8

Problem Solving

Recall → apply → unfamiliar context
● RED
9

Lesson Close

What you now know — and what comes next
● GREEN
Key ideas from this lesson
Electric current is the rate of flow of charge past a point: I = ΔQ / Δt. One ampere means one coulomb of charge per second. In metals, the carriers are electrons — moving opposite to the conventional current direction.
Potential difference is the energy transferred per unit charge between two points: V = W / Q. One volt = one joule per coulomb. Voltage is not energy — it is energy per coulomb.
Combining both: W = VIt = VQ. The charge that flows, the current, the voltage and the time are all related. The type of charge carrier (electron, ion, hole) depends on the material.
Next lesson
Resistance & Ohm's Law — now you know current and potential difference, the next question is: what property of a component determines how much current flows for a given voltage?
Retrieval prompt planted. In 4 lessons you will be asked to recall the definitions of current and potential difference from memory — with no notes. That difficulty is what makes memory last.